Question 91442
2X-3Y=1
-3Y=-2X+1
Y=-2X/-3+1/-3
Y=2X/3-1/3 THIS LINE HAS A SLOPE OF 2/3 SO A LINE WHICH IS PERPENDICULAR HAS A SLOPE OF -3/2. NOW USING THIS SLOPE & THE POINT (-4,8) IN THE LINE EQUATION 
[Y=mX+b] WE GET
8=-3/2*-4+b
8=12/2+b
8=6+b
b=8-6
b=2 THUS THE EQUATION OF THIS LINE IS:
Y=-3X/2+2