Question 1048417
<pre>
{{{24xy+25y^2-20x-30y^3}}}

Try to factor by grouping as they are arranged,

{{{cross(y(24x+25y)-10(2x-3y^2))}}}

No, that doesn't give us a common factor.

Rearrange by swapping the two middle terms:

{{{24xy-20x+25y^2-30y^3}}}

Try to factor by grouping as they are arranged

{{{cross(4x(6y-5)+5y^2(5-6y))}}}

Now we see we should have swapped the last two terms

{{{24xy-20x-30y^3+25y^2}}}

{{{4x(6y-5)-5y^2(6y-5)}}}

Now we have a common factor (6y-5)

{{{(6y-5)(4x-5y^2)}}}

Edwin</pre></b>