Question 1048322
If the frames take up 1/3 of the screen,
then the page itself takes up 2/3 of
the screen
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Let {{{ x }}} = the width of the frames
{{{ ( 7 - 2x )*( 11 - 2x ) = (2/3)*7*11 }}}
{{{ 3*( 77 - 22x - 14x + 4x^2 ) = 154 }}}
{{{ 231 - 108x + 12x^2 = 154 }}}
{{{ 12x^2 - 108x + 77 = 0 }}}
Solve using quadratic formula
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{ a = 12 }}}
{{{ b = -108 }}}
{{{ c = 77 }}}
{{{x = (-(-108) +- sqrt( (-108)^2-4*12*77 ))/(2*12) }}}
{{{x = ( 108 +- sqrt( 11664 - 3696 ))/24 }}}
{{{ x = ( 108 - sqrt( 7968 ) ) / 24 }}}
{{{ x = ( 108 - 89.264 ) / 24 }}}
{{{ x = 18.736/24 }}}
{{{ x = .78067 }}} 
The width of the frames is .78067 inches
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check:
{{{ ( 7 - 2x )*( 11 - 2x ) = (2/3)*7*11 }}}
{{{ ( 7 - 2*.78067 )*( 11 - 2*.78067 ) = (2/3)*7*11 }}}
{{{ ( 7 - 1.56134 )*( 11 - 1.56134 ) = 154/3 }}}
{{{ 5.43866*9.43866 = 51.333 }}}
{{{ 51.334 = 51.333 }}}
close enough -hope I got it!