Question 1823
these are always fun to do...pick 2 of the four terms and factorise those, then do the other 2 terms. Hopefully you will then have 2 sets of factors that have a common term. This is the whole point of these questions...the solution should be there, just need to hunt for it...

1. {{{kj-60+10k-6j}}} becomes
{{{j(k-6) + 10(k-6)}}}
{{{(j+10)(k-6)}}}

2. {{{gh+12h+3h^2+4g}}} becomes
{{{g(h+4) + 3h(h+4)}}}
{{{(g+3h)(h+4)}}}

3. {{{2z^2+12x+3z+8xz}}} becomes
{{{z(2z+3) + 4x(2z+3)}}}
{{{(z+4x)(2z+3)}}}

cheers
Jon.