Question 1048360
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Hi,
     *[illustration rectangle.png].
P = 2L + 2w in general
Here: subdivided into 3 smaller pens (2w + w + w) extra widths for separation purposes (3 smaller pens)
180 yards of fencing material
180yd = 2L + 4w 
180dy = 2*60 + 4w
60dy = 4w
w = 15yd, how wide can the rectangle can  be with L = 60yd