Question 1048403

let numbers be {{{x}}} and {{{y}}}
if the sum of two numbers is {{{-62}}}, we know that {{{x+y=-62}}}....eq.1

if twice the first (which is {{{2x}}}) minus the second (which is {{{y}}}) is {{{41}}}, we know that {{{2x-y=41}}}.........eq.2

now we have system to solve:
{{{x+y=-62}}}....eq.1
{{{2x-y=41}}}.........eq.2
----------------------------------add eq.1 and eq.2

{{{x+y+2x-y=-62+41}}}

{{{x+cross(y)+2x-cross(y)=-21}}}

{{{3x=-21}}}

{{{x=-21/3}}}

{{{highlight(x=-7)}}}

now find {{{y}}}

{{{x+y=-62}}}....eq.1
{{{-7+y=-62}}}
{{{y=-62+7}}}
{{{highlight(y=-55)}}}

so, your numbers are:{{{highlight(-7)}}} and {{{highlight(-55)}}}

check:
{{{x+y=-62}}}....eq.1
{{{-7-55=-62}}}
{{{-62=-62}}}

{{{2x-y=41}}}.........eq.2
{{{2(-7)-(-55)=41}}}
{{{-14+55=41}}}
{{{41=41}}}