Question 1048317
Unclear if a particular technique is expected.


You can try to isolate one variable in terms of the other.
{{{AB=6B+6A}}}
{{{AB-6A=6B}}}
{{{A(B-6)=6B}}}

{{{A=(6B)/(B-6)}}}, and say y=A and x=B.  



{{{graph(400,400,-6,6,-6,6,6x/(x-6))}}}


Maybe more than one solution, but  B=2, A=-3 seems to be one.