Question 1048252
mean of 25, and a standard deviation of 4.
a) Use invNorm(.70) to find z = .5244
*Note: {{{z = blue(x - mu)/blue(sigma)}}} 0r {{{blue(sigma)*z  + mu = x}}}
4(.5244) + 25 = 27.0976   Round up to  nearest whole number
28, the lowest score someone can get and still earn a certificate 
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b) invNorm(.95) = 1.6449
4(1.6449) + 25 = x , the lowest score someone can get and still go onto compete with the rest of the state?