Question 1048191
let x be width then 
4+x is the lenght


{{{(x+4)(x)}}}={{{(2x)+2(4+x)+1}}}

{{{x^2-9}}}={{{0}}}
{{{(x-3)(x+3)}}}={{{0}}}
{{{x}}}={{{3}}} or {{{x}}}={{{-3}}}

width is 3
lenght is 7

check 
area is 21 which is 1 more than the perimeter which is 20.