Question 1048050
Let the consecutive integers be:
{{{ n }}}, {{{ n+1 }}}, and {{{ n+2 }}}
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{{{ n+ 2 + 2n = 41 }}}
{{{ 3n = 39 }}}
{{{ n = 13 }}}
and
{{{ n + 1 = 14 }}}
{{{ n + 2 = 15 }}}
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The numbers are 13, 14, and 15
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check:
{{{ n+ 2 + 2n = 41 }}}
{{{ 15 + 2*13 = 41 }}}
{{{ 15 + 26 = 41 }}}
{{{ 41 = 41 }}}
OK