Question 91400
We basically have the sequence:


{{{sqrt(1)}}}, {{{sqrt(3)}}}, {{{sqrt( 5)}}}, {{{sqrt( 7)}}}, and {{{sqrt( 9)}}}... 


since {{{sqrt(1)=1}}}



So if we just look at the numbers inside the root and ignore the root for now we get the sequence


1,3,5,7,9....



Since the distance from term to term is d=2 and the starting term is a=1, we get the sequence


{{{a[n]=2n+1}}} where we start at n=0



Now just place that sequence in a square root like this


{{{a[n]=sqrt(2n+1)}}}