Question 91393




Lets evaluate {{{f(0)}}}


{{{f(x)=x^2-7x+10}}} Start with the given polynomial



{{{f(0)=(0)^2-7(0)+10}}} Plug in {{{x=0}}}



{{{f(0)=(0)-7(0)+10}}} Raise 0 to the second power to get 0



{{{f(0)=(0)-0+10}}} Multiply 7 by 0 to get 0



{{{f(0)=10}}} Remove any zero terms



So when {{{x=0}}}, {{{f(0)=10}}}



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Lets evaluate {{{f(5)}}}


{{{f(x)=x^2-7x+10}}} Start with the given polynomial



{{{f(5)=(5)^2-7(5)+10}}} Plug in {{{x=5}}}



{{{f(5)=(25)-7(5)+10}}} Raise 5 to the second power to get 25



{{{f(5)=(25)-35+10}}} Multiply 7 by 5 to get 35



{{{f(5)=0}}} Now combine like terms



So when {{{x=5}}}, {{{f(5)=0}}}


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Lets evaluate {{{f(-2)}}}


{{{f(x)=x^2-7x+10}}} Start with the given polynomial



{{{f(-2)=(-2)^2-7(-2)+10}}} Plug in {{{x=-2}}}



{{{f(-2)=(4)-7(-2)+10}}} Raise -2 to the second power to get 4



{{{f(-2)=(4)--14+10}}} Multiply 7 by -2 to get -14



{{{f(-2)=4+14+10}}} Negate any negatives



{{{f(-2)=28}}} Now combine like terms



So when {{{x=-2}}}, {{{f(-2)=28}}}


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