Question 91201
{{{((x^2-x-20)/(x^2-3x-10))*((x^2+7x+10)/(x^2+4x-5))}}} Start with the given expression 



{{{(((x-5)(x+4))/(x^2-3x-10))*((x^2+7x+10)/(x^2+4x-5))}}} Factor {{{x^2-x-20}}} to get {{{(x-5)(x+4)}}}  (note: if you need help with factoring, check out this <a href=http://www.algebra.com/algebra/homework/playground/change-this-name4450.solver>solver</a>)


{{{(((x-5)(x+4))/((x-5)(x+2)))*((x^2+7x+10)/(x^2+4x-5))}}} Factor {{{x^2-3x-10}}} to get {{{(x-5)(x+2)}}}  


{{{(((x-5)(x+4))/((x-5)(x+2)))*(((x+5)(x+2))/(x^2+4x-5))}}} Factor {{{x^2+7x+10}}} to get {{{(x+5)(x+2)}}}  


{{{(((x-5)(x+4))/((x-5)(x+2)))*(((x+5)(x+2))/((x+5)(x-1)))}}} Factor {{{x^2+4x-5}}} to get {{{(x+5)(x-1)}}}  


{{{(((highlight(x-5))(x+4))/((highlight(x-5))(highlight(x+2))))*(((highlight(x+5))(highlight(x+2)))/((highlight(x+5))(x-1)))}}} Notice we have these common terms


{{{(((cross(x-5))(x+4))/((cross(x-5))(cross(x+2))))*(((cross(x+5))(cross(x+2)))/((cross(x+5))(x-1)))}}} They divide and cancel out


{{{(x+4)/(x-1)}}} Leaving you with this



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{{{(x^2+x-12)/(2x^2-3x-9)}}} Start with the given expression 



{{{((x+4)(x-3))/(2x^2-3x-9)}}} Factor {{{x^2+x-12}}} to get {{{(x+4)(x-3)}}}  (note: if you need help with factoring, check out this <a href=http://www.algebra.com/algebra/homework/playground/change-this-name4450.solver>solver</a>)




{{{((x+4)(x-3))/((x-3)(2x+3))}}} Factor {{{2x^2-3x-9}}} to get {{{(x-3)(2x+3)}}}  


{{{((x+4)*cross((x-3)))/(cross((x-3))(2x+3))}}} Notice we have these common terms that cancel out


{{{(x+4)/(2x+3)}}} Leaving you with this