Question 1047951
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The sum of the first n terms of a series is 2n^2−n. Find the nth term
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<pre>
{{{a[n]}}} = {{{S[n]}}} - {{{s[n-1]}}} = {{{2*n^2 -n}}} - {{{(2*(n-1)^2 - (n-1))}}} = {{{2n^2 - n - 2n^2 + 4n - 2 + n - 1}}} = 4n-3.


<U>Answer</U>.  {{{a[n]}}} = 4n-3.
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