Question 1047932
{{{g(f(x))=6(f(x))}}}
{{{g(f(x))=6(x+1)}}}
{{{g(f(x))=6x+6}}}



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Misunderstood.


The compositions are NOT equal.
{{{f(g(x))=(6x+1)=6x+1}}}



Question is, do these functions composed, {{{f(g(x))=g(f(x))}}}?
{{{6x+1=6x+6}}}  ?
NO.  The equality is FALSE.