Question 1047546
 If you sail a ship due east for 50km, then turn and head due south for 80km, how far are you from your starting point,
This is right triangle, using pythag a^2 + b^2 = c^2, where
a = 50
b = 80
c = dist from your starting point
c^2 = 50^2 + 80^2
c^2 = 8900
c = {{{sqrt(8900)}}}
c = 94.34 km from the starting point
:
what is the bearing of your ship from the starting point?
Bearing is in relationship to the the north/south line 
Using the cosine of the interior angle of triangle at the point of the ship (S)
cos(S) = {{{80/94.34)}}}
S = 32 degrees
Bearing from the starting point is the  = & opposite angle
South 32 East