Question 1047829
note logbase 2 of 2=1

{{{(1/2)^x}}}={{{64}}}
{{{(1/2)^x}}}={{{2^6}}}
{{{xlog}}} *{{{(1/2)}}}= 6log {{{2}}}

{{{xlog}}}* {{{(1/2)}}}= {{{6(1)}}}
{{{x(-1)}}}={{{6}}}
{{{x}}}={{{-6}}}