Question 1047845

if you are given these two functions: {{{ f(x) = a^2 - 2 ab + b^2c }}} and {{{ g(x) = -3b^2c + 6ab }}}

{{{ (f-g)(x)= f(x)-g(x)}}}

{{{ (f-g)(x)= a^2 - 2ab + b^2c-(-3b^2c + 6ab)}}}

{{{ (f-g)(x)= a^2 - 2ab + b^2c+3b^2c- 6ab}}}

{{{ (f-g)(x)= a^2- 8ab + 4b^2c}}}

so, answer is:

A.) {{{ a^2 - 8 ab + 4b^2c }}}