Question 1047791
1.  slope is -2 and through (3,0).  Point slope formula, y-y1=m(x-x1)
y-0=-2(x-3)
y=-2x+6
2.y-2=2(x-1)
y-2=2x-2, distributing
y=2x
3.Need slope first, which is change in y over change in x.  That is -9/12=-3/4
y+5=(-1/12)(x-7). You can use the other point if desired and watch the signs. 
y+5=(-x/12)+(7/12);5=60/12
y=-(1/12)x-(53/12)
check with other point
y+4=(1/12)(x+5)
y+4=(1/12)x-(5/12)
y=(-1/12)x-(53/12)
{{{graph(300,300,-10,10,-10,10,(-x/12)-(53/12))}}}
4.Just move the 6 to the other side.  That makes it standard form.
5x-y=-6.  The coefficient of y is implied -1, an integer.
5.y=-3x+9 is slope-intercept form.
Move the x to the other side and you are done.
3x+y=9.  This is standard form.  The x and y have to have integer coefficients, and the x one must be positive.  The constant is on the other side and has to be an integer.