Question 1047766
sorry i was in a hurry,hope this clears up.

the lenght of AB is {{{sqrt(45)}}}
three times is {{{3sqrt(45)}}}
slope of the line is {{{m}}}={{{-2x+2}}}

use distance formula for A(-1,4) or B(2,-2)
using B(2,-2)
{{{(x-2)^2+(-2x+2+2)^2}}}}={{{(3sqrt(45))^2}}}

simplify to get 
{{{(x^2-4x-77)}}}=0


using A(-1,4)
{{{(x+1)^2+(-2x+2-4)^2}}}={{{(3sqrt(45))^2}}}
Simplify to get
{{{(x^2+2x-80)}}}=0