Question 1047753
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find three consecutive odd integers such that the sum of the least integer and the middle integer 19 more than the great integer 
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<pre>
Let A = 2n+1 be the first (the least) of the three consecutive odd integers;
    B = 2n+3 be the second of the three consecutive odd integers; and
    C = 2n+5 be the third.

The condition requires

A + B = C + 19,  or

(2n+1) + (2n+3) = (2n+5) + 19.

Simplify:

2n + 1 + 2n + 3 = 2n + 5 + 19,

2n + 4 = 24,

2n = 24 - 4 = 20,

n = {{{20/2}}} = 10.

So, your numbers are A = 2n+1 = 2*10+1 = 21; B = 21+2 = 23;  and C = 23+2 = 25.

<U>Check</U>. A + B = 21 + 23 = 44.
        44 - 19 = 25.   Correct !

<U>Answer</U>. The numbers are 21, 23 and 25.
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