Question 1047696
Two ships leave port in different directions.
 The first ship leaves at 8AM traveling due east at 32 knots.
 The second ship leaves three hours later traveling due north at 36 knots.
 How far apart are the two ships at 11PM.
 (1 knot= 1 nautical mile per hour. Round your answers to two decimal places.)
:
The first ship leaves at 8 am
the second ship leaves at 11 am
:
The travel time of the 1st ship; 8am to 11pm = 15 hrs
the travel time of the 2nd ship; 11am to 11pm = 12 hrs
:
The first ship travels 32 * 15 = 480 n mi
The second ship travels 36 * 12 = 432 n mi
:
The dist between the ships is the hypotenuse of a rt triangle
a^2 + b^2 = c^2
where
a = 480 mi
b = 432 mi
c = distance between them
:
c = {{{sqrt(480^2 + 432^2)}}}
c = 645.77 naut mi