Question 1047698
m1 = (x * y) / z^2


m2 = (2 * x * 10 * y) / (3 * z^2)


m2 / m1 = [(2 * x * 10 * y) / (3 * z^2)] / [(x * y) / (z^2)]


since (a/b) / (c/d) is the same as (a/b) * (d/c), your equation becomes:


m2 / m1 = (2 * x * 10 * y) / (3 * z^2) * (z^2) / (x * y)


this is equivalent to:


m2 / m1 = (2 * x * 10 * y * z^2) / (3 * z^2 * x * y)


the x and the y and the z^2 in the numerator cancel out the x and the y and the z^2 in the denominator and you are left with:


m2 / m1 = (2 * 10) / 3 which is equal to 20/3.


multiply both sides of this equation by m1 and you get:


m2 = 20 / 3 * m1


this says that m2 is 20/3 times as large as m1.


to see if this is correct, just provide random values for x, y, and z, and see if the ratio is correct.


i used:


x = 5
y = 10
z = 15


m1 = x * y / z^2 becomes m1 = (5 * 10) / (225) which becomes m1 = 50 / 225


m2 = (2 * x * 10 * y) / (3 * z^2) becomes m2 = (2 * 5 * 10 * 10) / (3 * 225) which becomes m2 = 1000 / 675.


if you take 50 / 225 and multiply it by 20 / 3, you get 1000 / 675.


this confirmed, for me, that the solution is good and that m2 is 20/3 times as large as m1.


i believe this is what you're looking for.