Question 1047657
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Your function has 3 zeros, -2, 1, and 3.  These three values divide the *[tex \Large x] axis into four regions, less than -2, between -2 and 1, between 1 and 3, and greater than 3.


For each one of these regions, select a value that is NOT one of the zeros.  I chose -3, 0, 2, and 4.  Take each of these values and substitute into the function.  You don't need to calculate the actual value of the function, you just need to determine the sign of each of the factors. Counting the -2 lead coefficient, count the number of negative factors for each one of the selected values. If you have an even number of negative factors, then the value of the function on that interval is positive.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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