Question 1047633
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2(x\ -\ 1)\ \geq\ 2x\ +\ 10]


Distribute the 2 in the LHS.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2x\ -\ 2\ \geq\ 2x\ +\ 10]


Add *[tex \Large -2x] to both sides.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ -2\ \geq\ 10]


Which is a false statement.  Therefore there is no value of *[tex \Large x] that makes the original equation true; the solution set is the empty set.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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