Question 1047635
 8x-3<8(x+2)
8x-3<8x+16
subtract 8x from both sides
-3<16.  This is true.  Therefore, every x works and there are infinite solutions.
Try 0
-3<16 yes
Try 10
77<8(12) yes
Try -10
-83<8(-8) yes
For an equality, -3=16 means no solutions.
For an inequality, -3>16 means no solutions, but -3<16 means infinite number of solutions.