Question 1047445

A passenger train traveled 100 miles in the same amount of time it took a fright train to travel 80 miles. The rate of the freight was 5 miles per hour slower than the rate of the passenger train. Find the rate of the passenger train 
<pre>Let rate of passenger train be S
Then rate of freight train is: S - 5
We then get the following TIME equation: {{{100/S = 80/(S - 5)}}}
100(S - 5) = 80S ------ Cross-multiplying
100S - 500 = 80S
100S - 80S = 500
20S = 500
S, or rate of passenger train was: {{{500/20}}}, or {{{highlight_green(matrix(1,2, 25, mph))}}}