Question 1047511

The sum of three consecutive odd integers is .11 more than twice the second one.  Find all three consecutive integers.  Show your work. 
<pre>Let first integer be F
Then others are: F + 2, and F + 4
We then get: F + F + 2 + F + 4 = 2(F + 2) + 11
3F + 6 = 2F + 4 + 11
3F - 2F = 15 - 6
F, or 1st integer = {{{highlight_green(9)}}}
2nd: 9 + 2
3rd: 9 + 4
It's very EASY.....far from being complex!