<PRE><B>Question 1047511</B>
The sum of three consecutive odd integers is .11 more than twice the second one. Find all three consecutive integers. Show your work.
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1st:: 2x-1
2nd:: 2x+1
3rd:: 2x+3
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Sum = 6x+3
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Equation:
6x+3 = 2(2x+1) + 11
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6x+3 = 4x +13
2x = 10
x = 5
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1st: 2x-1 = 9
2nd: 11
3rd: 13
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Cheers,
Stan H.</PRE>