Question 1047495
sqrt(x+2)-x=-4
sqrt(x+2)=x-4
square both sides
x+2=x^2-8x+16
x^2-9x+14=0
(x-7)(x-2)=0
x=7,2
Check for extraneous roots.
sqrt (9)-(7)=-4.  3-7=-4, so x=7 is a solution.
Try 2
sqrt(-2+2)-(2)=-4
0-2 does not equal 4.
f(7)=-4
{{{graph(300,300,-10,10,-10,10,sqrt(x+2)-x+4)}}}  This is a graph of sqrt(x+2)-x+4.  Where it equals 0 is a root of this function.