Question 1047404
(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6) 

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6) 

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6) 

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6) 

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)
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P(two no. 4s) = 1/36
P( two and a five) = P(2,5) + P(5,2) = 2/36 = 1/18
P(Obtaining only one two) = 5/36(2nd column - 2 second) + 5/36(2nd row - 2 first) = 10/36 = 5/18
P(Not obtaining two threes landing face up) = 1 - P(3,3) = 1-1/36 = 35/36