Question 1047388
If the diameter is multiplied by {{{ 3/2 }}},
then so is the eradius
Let {{{ f[1] }}} = the rate of flow through the pipe
Let {{{ r }}} = radius of the pipe
{{{ f[1] = k*r^2 }}}
{{{ k = f[1]/r^2 }}}
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{{{ f[2] = k*(( 3/2 )*r)^2 }}}
{{{ f[2] = ( f(1)/r^2 )*( (3/2)*r )^2 }}}
{{{ f[2] / f[1] = ( (3/2)*r )^2 / r^2 }}}
{{{ f[2] / f[1] = ( 9/4 )*( r^2/r^2 ) }}}
{{{ f[2] / f[1] = 9/4 }}}
The rate of flow is increased by a factor of 9/4