Question 91307
What is the maximum value of z=3x+y for the region given by the system:
x>= 0
y>= 0
These two conditions limit the search to the 1st Quadrant.
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1/2x+y<=11
Solve for y so you can graph this restriction:
y <= (-1/2)x + 11
{{{graph(400,300,-10,25,-10,25,(-1/2)x + 11)}}}
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Find the coordinates of the intersection points of the 
restricion lines.
Put those coordinate vales into the objective function, z=3x+y,
and see which coordinate pair give a maximum value.
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Cheers,
Stan H.