Question 1047327
log(3x+2)- log(3x-2)= log5
log(3x+2)/(log(3x-2)=log 5


(3x+2)/(3x-2)=5

3x+2=15x-10
12=12x
x=1

log 5 -log 1=log 5
log 5 -0=log 5
log 5=log 5