Question 1047304
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Hello i am confused as to where to start and solve this question

Write the expression in algebraic form.

Sin(arccos(x))
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<pre>
arccos(x) is the angle {{{alpha}}} whose cosine is "x": {{{cos(alpha)}}} = x.


Now, {{{sin(alpha)}}} = {{{sqrt(1-cos^2(alpha))}}}.

But cos(alpha) = x.  Hence, {{{sin(alpha)}}} = {{{sqrt(1-x^2)}}}.


Thus  sin(arccos(x) = {{{sin(alpha)}}} = {{{sqrt(1-x^2)}}}.


<U>Answer</U>.  sin(arccos(x) = {{{sqrt(1-x^2)}}}.
</pre>

To see more similar solved problems, look into the lessons

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/Trigonometry-basics/Calculating-trigonometric-functions-of-angles.lesson>Calculating trigonometric functions of angles</A>

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/Trigonometry-basics/Selected-problems-from-the-archive-on-calculating-trig-functions-of-angles.lesson>Advanced problems on calculating trigonometric functions of angles</A>

in this site.


They may help you in the future when you will meet similar problems.