Question 1047286
How do I find the solution to this equation by completing the square:

2x^2-5x=7

Thanks for any help.  
<pre>{{{2x^2 - 5x = 7}}}
{{{2x^2/2 - (5/2)x = (7/2)}}} ------- DIVIDING each side by 2 to make the LEADING coefficient, 1
{{{x^2 - (5/2)x = 7/2}}}
{{{x^2 - (5/2)x + (- 5/4)^2 = 7/2 + (- 5/4)^2}}} ------ Taking {{{matrix(1,10, (1/2), of, b, or, 1/2, of, - 5/2, which, "=", - 5/4))}}}, SQUARING it, and ADDING this result to EACH SIDE
{{{(x - 5/4)^2 = 7/2 + 25/16}}}
{{{(x - 5/4)^2 = 56/16 + 25/16}}} ------ Changing {{{7/2}}} to denominator, 16
{{{(x - 5/4)^2 = 81/16}}}
{{{sqrt((x - 5/4))^2 = " "+- sqrt(81/16)}}} ------- Taking square root of both sides
{{{x - 5/4 = " "+- 9/4}}}
{{{x = 5/4 +- 9/4}}}
{{{highlight_green(matrix(1,7, x = 5/4 + 9/4, or, x = 14/4, or, 7/2, or, highlight(3.5)))}}}        OR      {{{highlight_green(matrix(1,5, x = 5/4 - 9/4, or, x = - 4/4, or, highlight(- 1)))}}}