Question 1047265
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Any number with a units digit of 7 is an odd number.


1 raised to any power is 1; eliminate 1


2 raised to any power is even; eliminate 2


*[tex \Large 3^3\ =\ 27]; include 3


4 is *[tex \Large 2^2], so 4 raised to any power is even; eliminate 4


The units digit of *[tex \Large 5^n] is 5; eliminate 5


*[tex \Large 6\ =\ 2\ \times\ 3], so 6 raised to any power is even; eliminate 6


*[tex \Large 7^1\ =\ 7]; include 7


*[tex \Large 8\ =\ 2^3], so 8 raised to any power is even; eliminate 8


*[tex \Large 9^2\ =\ 27]; include 9


The units digit of *[tex \Large 10^n] is 0; eliminate 10.


In summary:  3, 7, and 9


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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