Question 1047243
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Because they are equivalent values. *[tex \Large a^{-1}\ =\ \frac{1}{a}\ \ \ \ \forall\ a\ \in\ \mathbb{R}\ :\ a\ \not =\ 0]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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