<PRE><B>Question 1047230</B>
To solve the problems, we need to arrange the equations into the slope-intercept form
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a) 6x=5y+1 and -12x+10y=1
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5y = -6x +1
y = (-6x/5) +(1/5)
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10y = 12x +1
y = (12x/10) +(1/10)
y = (6x/5) +(1/10)
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If the slopes are equal, then the lines are parallel 
If the slopes are negative reciprocals, then the lines are perpendicular
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The slopes are -6/5 and 5/5, the lines are neither parallel or perpendicular
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b) 6+4x=3y and 3x+4y=8
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3y = 4x +6
y = (4x/3) +2
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4y = -3x +8
y = (-3x/4) +2
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The slopes are 4/3 and -3/4, the lines are perpendicular
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