Question 1047183
Let the consecutive numbers be:
{{{ n }}}, {{{ n+1 }}}, and {{{ n+2 }}}
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given:
{{{ n + n + 1 + n + 2 = 1941 }}}
{{{ 3n + 3 =  1941 }}}
{{{ 3n = 1938 }}}
{{{ n = 646 }}}
and
{{{ n+1 = 647 }}}
{{{ n+2 = 648 }}}
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The 3 consecutive numbers are 646, 647, and 648
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check:
{{{ n + n + 1 + n + 2 = 646 + 647 + 648 }}}
{{{ n + n + 1 + n + 2  = 1941 }}}
OK