Question 90552
state and graph the solution set???
x/(x-3)<=-8/(x-6) 
Find the values x CANNOT take.
x cannot be 3 and x cannot be 6.
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Draw a number line; plot 3 and 6 on that number line.
You now have three intervals of points that may be solution points.
Pick a test point from each interval to determine if the selected 
interval is part of the solution set.
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Interval (-inf,3); select x=0; 0/(0-3)<=-8/(0-6) ; true so (-inf,3) is part of the solution.
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Interval (3,6); select x= 5; 5/(5-3)<=-8/(5-6) ; true so (3,6) is part of the
solution.
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Interval (6,inf); select x= 7; 7/(7-3)<=-8/(7-6); false so no solution here
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Final solution: (-inf,3)U(3,6)
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Cheers,
Stan H.