Question 1047135
Let's say they rowed 30 miles WITH the current in the same time it took them to row 16 miles AGAINST the current. Then:
30/(x+3)=16/(x-3)
16x+48=30x-90
14x=138
x=9.857 as the speed of the team in still water. &#9786;&#9786;&#9786;&#9786;