Question 91239
Question:


solve (x+4)^2=25


Answer:


 {{{(x+4)^2 = 25 }}}


Take square root on both sides...



==>  {{{sqrt(x + 4)^2 = sqrt(25) }}}



==>  x + 4 = 5 or -5


Suppose x + 4 = 5


Subtract 4 from both sides of the expression


==> x + 4 - 4 = 5 - 4 


==> x = 1



Suppose x + 4 = -5


Subtract 4 from both sides of the expression


==> x + 4 - 4 = -5 - 4


==> x = -9


So we have two values of x


Hence the solution is ,

x = 1 and x= -9



Hope  you found the explanation useful.


Regards.
praseena.