<PRE><B>Question 1046826</B>
plant A produced 8000 panels.


6% of the panels from plant A and 2% of the panels from plant B were defective.


how many panels did plant B produce if the overall percentage of defective panels from the two plants was 3%.


if x is the number of panels produced by plant A and y is the number of panels produced by plant B, then:


.06 * x + .02 * y = .03 * (x + y)


you know that x equals 8000, so the formula becomes:


.06 * 8000 + .02 * y = .03 * (8000 + y)


simplify this equation to get:


480 + .02 * y = 240 + .03 * y


subtract 240 from both sides of this equation and subtract .02 * y from both sides of this equation to get:


240 = .01 * y


solve for y to get:


y = 240 / .01 = 24,000.


plant B produced 24,000.


together they produced 8,000 + 24,000 = 32,000 panels.


.06 * 8000 = 480 defective from plant A.


.02 * 24000 = 480 defective from plant B.


total defective = 960.


total percent defective from both plants was 960 / 32000 * 100 = 3 %.



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