Question 1046853


the perimeter of a rectangle: {{{P=2(L+W)}}}

if a length {{{L}}} that is {{{5in}}} longer than the width {{{W}}}, we have {{{L=W+5in}}}

so, the perimeter will be {{{P=2(W+5in+W)}}}-> {{{P=2(2W+5in)}}}-> {{{P=4W+10in}}}