Question 1046823
z^2=5-12i
Where z=a+bi
:
Replace z with (a+bi)
(a+bi)^2 = 5 - 12i
:
FOIL (a+bi)(a+bi)
a^2 + 2abi + b^2i^2 = 5 -12i
:
i^2 = -1 therefore
a^2 + 2abi - b^2 = 5 - 12i
a^2 + 2abi = b^2 + 5 - 12i
a^2 + 2abi + 12i = b^2 + 5
:
I don't know what else you can do with it.