Question 1046836
p = 4/300 = 1/75 = .0133
n = 20
TI syntax for P(x-value) is binompdf(n, p, x-value).
⦁	Exactly one defective I-phone?  p =  binompdf(20, .0133, 1) = .2062
⦁	Exactly two defective I-phones? p =  binompdf(20, .0133, 2) = .2064
⦁	Exactly three defective I-phones? p =  binompdf(20, .0133, 3)= .0023 
⦁	Exactly four defective I-phones?  p = p =  binompdf(20, .0133, 4)= .0001
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