Question 91229
{{{sqrt(80*x^4)}}}Start with the given expression

{{{sqrt(16*5*x^4)}}} Factor {{{80}}} into {{{16*5}}}
 
{{{sqrt(16*5*x^2*x^2)}}} Factor {{{x^4}}} into {{{x^2*x^2}}}
 
{{{sqrt(16)*sqrt(5)*sqrt(x^2)*sqrt(x^2)}}} Break up the square root using the identity {{{sqrt(x*y)=sqrt(x)*sqrt(y)}}}
 
{{{4*sqrt(5)*sqrt(x^2)*sqrt(x^2)}}} Take the square root of the perfect square {{{16}}} to get 4 
 
{{{4*sqrt(5)*x*x}}} Take the square root of the perfect squares {{{x^2}}} to get  x
 
{{{4*sqrt(5)*x^2}}} Multiply the common terms 

{{{4*x^2*sqrt(5)}}} Rearrange the terms