Question 1046635
It's in vertex for so,
Vertex : ({{{6}}},{{{7}}})
Domain : All reals
Range: Since quadratic multiplier is negative, {{{7}}} is maximum. ({{{-infinity}}},{{{7}}}]
Y Intercept, set {{{x=0}}}
{{{y=-(2/3)(0-6)^2+7}}}
{{{y=-(2/3)(36)+7}}}
{{{y=-24+7}}}
{{{y=-17}}}
({{{0}}},{{{-17}}})
X intercept, set {{{y=0}}}
{{{0=-(2/3)(x-6)^2+7}}}
{{{(2/3)(x-6)^2=7}}}
{{{(x-6)^2=21/2}}}
{{{x-6=0 +- sqrt(21/2)}}}
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*[illustration sn3.PNG].
{{{x=6 +- sqrt(21/2)}}}
{{{x=6 +- sqrt(42)/2}}}