Question 1046624
.
There is a collection of nickels, dimes, and quarters with total value of $47.60. 
There are 28 more dimes than nickels. There are 5 times as many quarters as dimes. 
How many quarters are in the collection?
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<pre>
Let "d" be the number of dimes.

Then the number of quarters is 5d,
and the number of nickels is d-28, according to the condition.

Hence, the total in cents is

10d + 25*(5d) + 5*(d-28) = 4760,  or

10d + 125d + 5d - 140 = 4760,  or

140d = 4760 + 140,

d = {{{4900/140}}} = 35.

So, there are 35 dimes in the collection.

Then the number of quarters is 5*35 = 175 and the number of nickels is 35 - 28 = 7.

<U>Check</U>.  5*7 + 10*35 + 25*175 = 4760.   Correct !

<U>Answer</U>. 7 nickels, 35 dimes and 175 quarters.
</pre>

There is a bunch of my lessons on coin problems

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=http://www.algebra.com/algebra/homework/word/coins/Coin-problems.lesson>Coin problems</A>

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=http://www.algebra.com/algebra/homework/word/coins/More-Coin-problems.lesson>More Coin problems</A>

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=http://www.algebra.com/algebra/homework/word/coins/Solving-coin-problem-without-equations.lesson>Solving coin problems without using equations</A>

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/word/coins/Kevin-and-Randy-Muise-have-a-jar.lesson>Kevin and Randy Muise have a jar containing coins</A>

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/word/coins/Typical-coin-problems-from-the-archive.lesson>Typical coin problems from the archive</A>

in this site.


Read them and become an expert in counting coins.


Also, you have this free of charge online textbook in ALGEBRA-I in this site

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson>ALGEBRA-I - YOUR ONLINE TEXTBOOK</A>.


which contains many other word problems and many other interesting anf useful things.